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-0.5x^2+1.5x+2=0
a = -0.5; b = 1.5; c = +2;
Δ = b2-4ac
Δ = 1.52-4·(-0.5)·2
Δ = 6.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.5)-\sqrt{6.25}}{2*-0.5}=\frac{-1.5-\sqrt{6.25}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.5)+\sqrt{6.25}}{2*-0.5}=\frac{-1.5+\sqrt{6.25}}{-1} $
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